Kentucky: Number one in obscenity


Image by Billy Currell, who takes KFC to new highs and lows at Kentucky Fried Tender. Well, as a friend used to tell me, “He may be the Colonel to you, but he’s Hitler to us chickens.”

Not long ago I blogged about the legal team who wants to use Google Trends as an arbiter for community standards in a Florida obscenity case. I missed it in the first round, but Silicon Alley Insider took that logic a step further and using Google Trends, came up with a list of the ten most obscene cities in the U.S. The winner? Louisville, KY. San Francisco didn’t even make the list — for shame! The explain their methodology in the post, but here’s a snip from the middle:

The idea: If Google proves that local residents search for “sex” more than they do for, well, anything else, then the defense can argue that Internet pornographers are just satisfying a local need, not corrupting innocent minds. We like this idea, though we’re dubious that the courts are going to go for it.

But suppose they do? Where then, according to Google, does an obscenity defendant stand the best chances? In other words: What city’s residents are most interested in looking up dirty stuff on the Web?

Google Trends says: Louisville, Kentucky.

We know! We were surprised, too — almost as surprised as we were to see neither New York City or San Francisco in our top 10. The full list:

The 10 American Cities Most Likely To Search For Obscene Material

1. Louisville, KY
2. Rochester, NY
3. Philadelphia, PA
4. Newark, NJ
5. Los Angeles, CA

(…read more.)

One Comment - COMMENTARY is DESIRED

  1. Yep, I made the right decision to relocate here last October, and I welcome all of my motherfucking porn with my motherfucking arms wide fucking open.

    Better luck next year for SFO, Ms. Blue. You have my condolences.

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